I'd like to build a storage tank that is not too big and not too small - just right.
I am remodeling a house that I've energy modeled with a heat loss of ~20,000 BTUs/hour at 0 degree design temperature. I know that my energy model is accurate as I've done the same modeling on my existing house. Over a 24 hour period, the heat loss realistic worst case is 480,000 BTUs if the mean temperature for the full day is 0 degrees F. I don't need a massive amount of storage.
I am planning on installing a gasification boiler with lambda control. The model I am looking at has a 5 cubic foot firebox that is 22" deep. If I cut the wood for it 18" long, then I theoretically could fit 4 cubic feet of wood in it, but realistically, it will be less to account for air gaps. I am thinking that 2.5 cubic feet is probably right - I would welcome some advice here. What should I assume?
I'd like to build a water storage tank to take one full load of hard maple. The reason for this is that my wife will likely not follow "rules" about how much wood to put in the boiler. Therefore, the most simple rule is "fill it until it is full, or less". If this "rule" is followed (it would be hard to break this rule) the tank would not overheat provided a fire wasn't started until the tank temperature dropped below a certain value.
I can calculate the BTU of a wood load once I know the cubic feet of wood that will realistically fit in the firebox. Sugar Maple is 44 lbs. per cubic foot. Using Jebatty's rule of 6000 BTUs per pound, I can calculate BTUs in the wood, and multiple by the efficiency. Is the efficiency 80% for a lambda controlled boiler? If I had a good number for that, I could calculate BTUs produced per load. Example:
2.5 cubic feet * 44 lbs/cu foot * 6000 BTUs per pound *80% efficiency = 528,000 BTUs. To absorb this burn I would need approximately 1000 gallons of storage (8340 lbs. with a 60 degree temperature rise).
Are my assumptions good?
I am remodeling a house that I've energy modeled with a heat loss of ~20,000 BTUs/hour at 0 degree design temperature. I know that my energy model is accurate as I've done the same modeling on my existing house. Over a 24 hour period, the heat loss realistic worst case is 480,000 BTUs if the mean temperature for the full day is 0 degrees F. I don't need a massive amount of storage.
I am planning on installing a gasification boiler with lambda control. The model I am looking at has a 5 cubic foot firebox that is 22" deep. If I cut the wood for it 18" long, then I theoretically could fit 4 cubic feet of wood in it, but realistically, it will be less to account for air gaps. I am thinking that 2.5 cubic feet is probably right - I would welcome some advice here. What should I assume?
I'd like to build a water storage tank to take one full load of hard maple. The reason for this is that my wife will likely not follow "rules" about how much wood to put in the boiler. Therefore, the most simple rule is "fill it until it is full, or less". If this "rule" is followed (it would be hard to break this rule) the tank would not overheat provided a fire wasn't started until the tank temperature dropped below a certain value.
I can calculate the BTU of a wood load once I know the cubic feet of wood that will realistically fit in the firebox. Sugar Maple is 44 lbs. per cubic foot. Using Jebatty's rule of 6000 BTUs per pound, I can calculate BTUs in the wood, and multiple by the efficiency. Is the efficiency 80% for a lambda controlled boiler? If I had a good number for that, I could calculate BTUs produced per load. Example:
2.5 cubic feet * 44 lbs/cu foot * 6000 BTUs per pound *80% efficiency = 528,000 BTUs. To absorb this burn I would need approximately 1000 gallons of storage (8340 lbs. with a 60 degree temperature rise).
Are my assumptions good?