ISeeDeadBTUs said:
But which is better . . .
1) Gaining an extra 2% MC, or
2)Having the 180lb load of wood pre heated to say 50 deg ??
Well, lets see...mathematically (and making a few assumptions
[ wow, it's a slow day to work through this!]
180 lbs of wood, 2% moisture = 180 lbs wood x 0.02 = 3.6 pounds of water
Heat required to vaporize 3.6 lbs of frozen water =
Ice @ 32F to water @ 32F = 144 btu/lb x 3.6lb = 518 btu
Water @32F to water @ 212 F = 1 btu/lb per degree = 1 x 3.6 x 180 = 648 btu
Water @ 212F to steam @ 212F = 540 btu/lb x 3.6 lb = 1944 btu
So, assuming you had 180 lbs of frozen wood @ 15% MC, you'd expect about 7600 btu/lb or 180 x 7600 = 1.368 million btu. (call it 1.4 million btu for a round number) If that wood had 17% MC at the same starting temp, you'd expect (518 + 648 + 1944) = 3100 btu to be used simply vaporizing the additional water. You'd only get ~ 1.396 million btu out.
That's why I belong to this forum!
ie - the wet wood cost you 3100 btu
For cold wood, It looks like most hardwoods have a specific heat of ~ .287 btu/lb-F, so to raise 180 lbs of wood from 32F to 50F would take 180 x (50F-32F) x .287 = 1446 btu
so warming the wood saved 1446 btu
Overall, on these specific conditions, you'd be better off with dry wood versus warm wood. Though you also have to consider where the warmth for the wood came from in the first place...if it happened to be solar or some other external source, then this is truly a gain. If the heat came from simply being in the same room from the stove - then you've only moved heat from the room into the wood...you haven't really gained anything.