Hey all,
With the hope that someone will find this useful - I found on on the net showing how to make wall shields and floor protectors for UL listed stoves from Durock cement board: (broken link removed).
It says that Durock has a thermal conductivity of k <= 0.84 Btu in./(ft.2 h °F) in the minimum dimensions specified by the room heater/stove manufacturer. I was trying to figure out the R-value using formula R= 1/k x T from my Jotual manual. With T being thickness in inches, I calculate an R-value of .60 for the 1/2" inch thick board. Can anyone tell me if .60 is correct?
With the hope that someone will find this useful - I found on on the net showing how to make wall shields and floor protectors for UL listed stoves from Durock cement board: (broken link removed).
It says that Durock has a thermal conductivity of k <= 0.84 Btu in./(ft.2 h °F) in the minimum dimensions specified by the room heater/stove manufacturer. I was trying to figure out the R-value using formula R= 1/k x T from my Jotual manual. With T being thickness in inches, I calculate an R-value of .60 for the 1/2" inch thick board. Can anyone tell me if .60 is correct?